-4x^2-24x-32=0

Solution for -4x^2-24x-32=0 equation:

-4x^2-24x-32=0

a = -4; b = -24; c = -32;
Δ = b2-4ac
Δ = -242-4·(-4)·(-32)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8}{2*-4}=\frac{16}{-8}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8}{2*-4}=\frac{32}{-8}
=-4
$